10c^2+29c-21=0

Solution for 10c^2+29c-21=0 equation:

Simplifying
10c2 + 29c + -21 = 0

Reorder the terms:
-21 + 29c + 10c2 = 0

Solving
-21 + 29c + 10c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-7 + -2c)(3 + -5c) = 0

Subproblem 1
Set the factor '(-7 + -2c)' equal to zero and attempt to solve:

Simplifying
-7 + -2c = 0

Solving
-7 + -2c = 0

Move all terms containing c to the left, all other terms to the right.

Add '7' to each side of the equation.
-7 + 7 + -2c = 0 + 7

Combine like terms: -7 + 7 = 0
0 + -2c = 0 + 7
-2c = 0 + 7

Combine like terms: 0 + 7 = 7
-2c = 7

Divide each side by '-2'.
c = -3.5

Simplifying
c = -3.5
Subproblem 2
Set the factor '(3 + -5c)' equal to zero and attempt to solve:

Simplifying
3 + -5c = 0

Solving
3 + -5c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -5c = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -5c = 0 + -3
-5c = 0 + -3

Combine like terms: 0 + -3 = -3
-5c = -3

Divide each side by '-5'.
c = 0.6

Simplifying
c = 0.6
Solution
c = {-3.5, 0.6}